OK but it is not even 9.1K because it is for 9 ohm secondary load?Here are the parameters. Thoughts?
the impedance square ratio is 9100 / 9 = 1011
So with 8 R load it will be about 8090 R @ anode load
and with 7 R it will be 7080 R @ anode...
Anyway the slope will be slightly different, little bit more power but also more THD
...
The same Q for the power transformer - is it 2 x 800Vac with C.T (1600Vac)800-0-800 with 48R DCR for each secondary???
.
Please also write the values of power chokes L and Rdc
Is these values like on the PSUD schemais of power supply?
.
Thanks
C1=1uF in Your schematic. Check the peak voltage on that C...The first C (large C, not the small 1uF c) is rated for 1100V.
48R DCR in each 800V coil?PT is 800-0-800.
I asked it, because each tube rectifier requires definite RDC for given current, so series resistance (on each anode) may be necessary (must to calculate its value).
BTW, Pat you want to use 866 as rectifier?
I use mercury vapour rectifiers, using them is not an easy thing.
Preheating requires for MV heaters, even few minute heating before the main PT (HV secondary) turn on.
BTW, Pat you want to use 866 as rectifier?
I use mercury vapour rectifiers, using them is not an easy thing.
Preheating requires for MV heaters, even few minute heating before the main PT (HV secondary) turn on.
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